Tag Archives: Cyclic Prefix

Can We Do Without a Cyclic Prefix

Have you ever thought that Cyclic Prefix in OFDM is just a gimmick and we could do equally well by using a guard period i.e. a period of no transmission between two OFDM symbols. Well, one way to find out if this is true is by running a bit error rate simulation with and without a cyclic prefix (only a vacant guard period). We use the 64-QAM OFDM simulation that we developed previously. The channel is modeled as 7-tap FIR filter with each tap having a Rayleigh distribution.

BER with and without Cyclic Prefix
BER with and without Cyclic Prefix

We simulate the case of a vacant guard period by inserting zeros in the time slot dedicated for the CP (32 samples). It is observed that there is a vast difference in the bit error rate (BER) for the two cases. In fact in the case of no CP the BER hits an error floor at around 20 dB. Increasing the signal to noise ratio does not improve the BER performance any further.

Now to answer the question “why does the CP work” we have to revisit the concept of circular convolution from our DSP course. It is well known that performing circular convolution of two sequences in the time domain is equivalent to multiplication of their DFT’s in the frequency domain. So if a wireless channel performed circular convolution we could do simple division to recover the signal after the FFT operation in the receiver.

Y(k)=X(k)*H(k) Effect of Wireless Channel

X(k)=Y(k)/H(k) Recovery of the Signal

But the wireless channel does not perform circular convolution, it performs linear convolution. So the trick is to make this linear convolution appear as circular convolution by appending a cyclic prefix. The result is that equalization can be performed at the receiver by simple division.

For a more elaborate discussion on this you may visit CP-1 or for a mathematical description you may visit CP-2.

Note: In a actual system there would be AWGN noise added to the received signal as well. Giving us the following relationships.

Y(k)=X(k)*H(k)+W(k) Effect of Wireless Channel

X(k)’=Y(k)/H(k)=X(k)+W(k)/H(k) Recovery of the Signal