{"id":4139,"date":"2022-03-16T15:25:06","date_gmt":"2022-03-16T15:25:06","guid":{"rendered":"http:\/\/www.raymaps.com\/?p=4139"},"modified":"2024-12-09T06:41:33","modified_gmt":"2024-12-09T06:41:33","slug":"5g-data-rates-and-shannon-capacity","status":"publish","type":"post","link":"https:\/\/www.raymaps.com\/index.php\/5g-data-rates-and-shannon-capacity\/","title":{"rendered":"5G Data Rates and Shannon Capacity"},"content":{"rendered":"\n

Recently I came across a post from T-Mobile<\/strong><\/a> in which they claim to have achieved a download speed of 5.6 Gbps over a 100 MHz channel resulting in a Spectral Efficiency of more than 50 bps\/Hz. This was achieved in an MU-MIMO configuration with eight connected devices having an aggregate of 16 parallel streams i.e. two parallel streams per device. The channel used for this experiment was the mid-band frequency of 2.5 GHz.<\/p>\n\n\n\n

Now let us revisit the Shannon Capacity theorem and see what\ndata rate it predicts with the above parameters. Shannon Capacity theorem is\ngiven as:<\/p>\n\n\n\n

C = N x BW x log2(1+SNR)<\/strong><\/p>\n\n\n\n

N=16<\/strong> is the number of parallel streams enabled by multiple antennas at Tx and Rx<\/p>\n\n\n\n

BW=100 MHz<\/strong> is the total bandwidth available to the carrier in the 2.5 GHz band<\/p>\n\n\n\n

SNR=10<\/strong> is the Signal to Noise Ratio (a moderately good SNR is assumed)<\/p>\n\n\n\n

Plugging these numbers in, we get a capacity limit of 5.54\nGbps, approximately the same number obtained in the experiment. But it all\ndepends upon the Signal to Noise Ratio, that has not been mentioned by T-Mobile\nin the reference post. With an SNR=20 dB, a very good channel condition, the\ncapacity increases to about 10.65 Gbps but with an SNR=0 dB, a likely scenario\nat the cell edge, the capacity drops to 1.6 Gbps. The details for the capacity\nat different SNRs are given in the table and figure below.<\/p>\n\n\n\n

\"5G
5G Shannon Capacity Table<\/figcaption><\/figure>\n\n\n\n
\"5G
5G Capacity vs SNR<\/figcaption><\/figure>\n\n\n\n
    \n
  1. Please note that the above capacity calculations are for eight users simultaneously connected over the 100 MHz channel. The data rate achieved by a single user, in the T-Mobile experiment, was 5600\/8=700 Mbps.<\/li>\n\n\n\n
  2. Also note that much higher bandwidths are available in the millitmeter wave band and this may increase the data rates 10 fold or even higher.<\/li>\n<\/ol>\n\n\n\n

    References: <\/p>\n\n\n\n

    https:\/\/www.t-mobile.com\/news\/network\/t-mobile-achieves-mind-blowing-5g-speeds-with-mu-mimo<\/a><\/p>\n\n\n\n

    https:\/\/www.waveform.com\/a\/b\/guides\/5g-and-shannons-law<\/a><\/p>\n\n\n\n

    <\/p>\n","protected":false},"excerpt":{"rendered":"

    Recently I came across a post from T-Mobile in which they claim to have achieved a download speed of 5.6 Gbps over a 100 MHz channel resulting in a Spectral Efficiency of more than 50 bps\/Hz. This was achieved in an MU-MIMO configuration with eight connected devices having an aggregate of 16 parallel streams i.e. two parallel streams per device. The channel used for this experiment was the mid-band frequency of 2.5 GHz.<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[189,22,81],"tags":[195,238,42,28,29],"class_list":["post-4139","post","type-post","status-publish","format-standard","hentry","category-5g","category-capacity","category-fundamentals","tag-5g","tag-mid-band","tag-mimo","tag-shannon-capacity","tag-snr"],"_links":{"self":[{"href":"https:\/\/www.raymaps.com\/index.php\/wp-json\/wp\/v2\/posts\/4139","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.raymaps.com\/index.php\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.raymaps.com\/index.php\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.raymaps.com\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.raymaps.com\/index.php\/wp-json\/wp\/v2\/comments?post=4139"}],"version-history":[{"count":19,"href":"https:\/\/www.raymaps.com\/index.php\/wp-json\/wp\/v2\/posts\/4139\/revisions"}],"predecessor-version":[{"id":4532,"href":"https:\/\/www.raymaps.com\/index.php\/wp-json\/wp\/v2\/posts\/4139\/revisions\/4532"}],"wp:attachment":[{"href":"https:\/\/www.raymaps.com\/index.php\/wp-json\/wp\/v2\/media?parent=4139"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.raymaps.com\/index.php\/wp-json\/wp\/v2\/categories?post=4139"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.raymaps.com\/index.php\/wp-json\/wp\/v2\/tags?post=4139"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}