1000 x 0.20 x A = 25000

200 x A = 25000

A = 25000 / 200

A = 125 square meters

This is for panels lying flat on the ground. We would suggest that an area of at least 200 square meters must be reserved due to the following three reasons.

– Panels are not usually flat, they are placed at an angle and need more spacing so they do not shade each other, depends on your location

– You might need more panels for achieving peak generation of 25 KW, again depends on your location

– Panels might not achieve 20% efficiency that we have assumed above (the 0.20 factor that we used above was to cater for panel efficiency)

http://affordable-solar.com/site/images/learn/calculatingarrayarticleimage1.jpg

For calculation of batteries we need to know the load and the backup hours required. If you want a simplistic answer I would suggest that you put in 50 batteries of 200 AH each for a backup of about 5 hours.

]]>600 kWatt x 5 hours/day x 30 days/month = 90,000 kWHr/month

]]>A x 1000 x 0.2 Watts of power

Set this equal to the required power of 2000,000 Watts

A x 1000 x 0.2 = 2000,000

=> A = 10,000 meter squared

So the area you have 3000 square meter is not sufficient to produce 2000 kW of power.

One square meter can produce about 200 Watts and the cost of the solar system is about $1 to $2 per Watt depending upon how much backup you want. Solar panels can produce peak power for about 5 hours daily.

With the area you have you can produce 3000 x 200 = 600,000 Watts (600 kW) of peak electric power.

Lastly power is in Watts and monthly generation of energy is in KWHr, so please be careful with calculations.

]]>total area of roof top is 3000 metre squre .i need 30000 KW power consumption per month.almost 2000 kw per day consumption.could you please give me the desighn data for solar panel.

we need

1) maximum amount of kw produced for one metre squre panel and the cost of one metre squre panel

2) finally we need 2000 kw per day please give the sample calculation .

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