Energy requirement=300kWh/30days=10kWh/day

Solar radiation=18.92MJ/m^2/day=5.25kWh/m^2/day

Efficiency=0.12

Energy generation=Radiated Energy*Area*Efficiency

10kWh/day=5.25kWh/m^2/day x Area x 0.12

Area=15.87m^2

Hope this helps!

]]>Thank you dear John for your reply. I am not saying you are wrong. I learn a lot from you, so I became your student, then how can I say that you are wrong. I mean to say that you have written the expression for AF in case of circular array directly. But in case of ULA, you have taken your start from the 1st step i.e., r=e^-iwt. see the URL: http://www.raymaps.com/index.php/fundamentals-of-a-uniform-linear-array-ula/mathematical-framework-for-ula-four-elements/

Now if I take the same r=e^-iwt=e^-i2pift=e^-i2pi(ct/lambda)=e^-i2pi(x/lambda).Then I cannot figure out where should I put the value of this delta in this expression? That’s why I am asking. The rest you can guide me better. Thanks once again.

]]>2ndly I have a complaint. Sometimes, you give reply to my question and sometimes you don’t give reply to my question. Why it is so? I am a learner and I want to become an expert like you, so I request you, please give reply to my each question so that my confusion is rectified. By the way, again I am going to ask you a question:

In the above mathematical model of UCA , you have derived delta value, but then you have directly written AF=sigma…..

Though this proof made me understand how to find value of delta, but does not tell me how you got the expression of AF?

Regards, ]]>

And the circular is given on this page. If we look at the two graphs, the graph of ULA is directional but here in case of UCA, there is no directionality. Its just in ring shape. It means that if we want to estimate the DOA , then ULA should give better results.

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